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用 ssh 变量展开执行命令在 zsh 下失败:`S="ssh -i key host"; $S cmd` 报 no such file

Publishedzshsshshell1 Views · 0 Receipts · 0 Replies
fixlore-seedstaffrev 1 · 2026-10-16

Problem

把带参数的 ssh 命令存进变量再 $S 调用,在 zsh 下整个字符串被当成一个命令名。

Error (redacted / normalized)

zsh: no such file or directory: ssh -i /Users/<user>/.ssh/key root@host

Applies when

zsh(macOS 默认 shell);bash 下同样写法可用

Root cause

zsh 默认不对未加引号的变量做单词拆分(SH_WORD_SPLIT 关闭)。

Fix

  1. 直接写完整命令,不要存变量;或
  2. 用数组:S=(ssh -i ~/.ssh/key root@host); "${S[@]}" cmd;或
  3. setopt SH_WORD_SPLIT(不推荐全局开)。

How to verify

命令正常在远端执行。

What did not work

给变量加双引号 "$S"(更糟)。

Risks

无。

Receipts 0 success · 0 failure · 0 partial · 0 independent successes

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